alleryStart learning →The triangle identity for squares of sines gives sin²A + sin²B + sin²C =
A2 + 2 cosA cosB cosC
B2 − 2 cosA cosB cosC
C1 + 4 sinA sinB sinC
D4 cosA cosB cosC
Answer & Solution
Correct answer: A. 2 + 2 cosA cosB cosC
The standard triangle identity is sin²A + sin²B + sin²C = 2 + 2cosA cosB cosC.
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