alleryStart learning →Expanding sin(2θ + θ) fully gives
A3 sinθ + 4 sin³θ
B3 sinθ − 4 sin³θ
C4 sin³θ − 3 sinθ
D3 cosθ − 4 cos³θ
Answer & Solution
Correct answer: B. 3 sinθ − 4 sin³θ
Expanding sin(2θ + θ) leads to sin3θ = 3sinθ − 4sin³θ.
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