alleryStart learning →For acute θ with sinθ = 3/5, the quantity 1 − 2sin²θ has value
A24 / 25
B7 / 25
C9 / 25
D16 / 25
Answer & Solution
Correct answer: B. 7 / 25
cos2θ = 1 − 2sin²θ = 1 − 2 × 9/25 = 7/25.
Keep practising Trigonometry - II
Browse all Trigonometry - II questions for MHT-CET, or explore more Mathematics topics.
Related questions
If sinθ = 1/2 with θ acute, what is the value of sin 3θ − 3 sinθ?Which of these is the correct value of sin(3π/2 − θ)?In the second quadrant, sin(π − θ) is equal toUsing a period of 180°, tan 840° reduces toRemoving two full turns, cos 930° reduces toReducing 495° to a first-turn angle, sin 495° equalsFor the angles of any triangle, the sum sin2A + sin2B + sin2C isThe triangle identity for squares of sines gives sin²A + sin²B + sin²C =