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The ratio sin 2θ can be written in terms of tanθ as

A2 tanθ / (1 − tan²θ)
B(1 − tan²θ) / (1 + tan²θ)
C2 tanθ / (1 + tan²θ)
Dtanθ / (1 + tan²θ)
Answer & Solution
Correct answer: C. 2 tanθ / (1 + tan²θ)
Writing 2 sinθ cosθ as 2 tanθ cos²θ and using cos²θ = 1/(1 + tan²θ) gives 2tanθ/(1 + tan²θ).
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