Expressing tan 2θ through tanθ alone yields
A2 tanθ / (1 − tan²θ)
B2 tanθ / (1 + tan²θ)
C(1 − tan²θ) / 2 tanθ
Dtanθ / (1 − 2 tan²θ)
Answer & Solution
Correct answer: A. 2 tanθ / (1 − tan²θ)
Putting A = B = θ in tan(A + B) gives 2tanθ/(1 − tan²θ).
Keep practising Trigonometry - II
Browse all Trigonometry - II questions for MHT-CET, or explore more Mathematics topics.
Related questions
If sinθ = 1/2 with θ acute, what is the value of sin 3θ − 3 sinθ?Which of these is the correct value of sin(3π/2 − θ)?In the second quadrant, sin(π − θ) is equal toUsing a period of 180°, tan 840° reduces toRemoving two full turns, cos 930° reduces toReducing 495° to a first-turn angle, sin 495° equalsFor the angles of any triangle, the sum sin2A + sin2B + sin2C isThe triangle identity for squares of sines gives sin²A + sin²B + sin²C =