The expansion of tan(A − B) is
A(tanA + tanB) / (1 − tanA tanB)
B(tanA − tanB) / (1 − tanA tanB)
C(tanA − tanB) / (1 + tanA tanB)
D(1 + tanA tanB) / (tanA − tanB)
Answer & Solution
Correct answer: C. (tanA − tanB) / (1 + tanA tanB)
Replacing B by −B in the tan(A + B) formula gives (tanA − tanB)/(1 + tanA tanB).
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