A platinum resistance thermometer reads 5.00 Ω at 0°C and 5.23 Ω at 100°C. When its resistance is 5.795 Ω, the temperature is about:
A345 °C
B100 °C
C580 °C
D200 °C
Answer & Solution
Correct answer: A. 345 °C
t = (R_t − R_0)/(R_100 − R_0)×100 = (5.795 − 5)/(5.23 − 5)×100 = (0.795/0.23)×100 ≈ 345 °C.
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