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For y = sin^-1 x with first and second derivatives y1 and y2, which holds?
A(1 - x^2) y2 - x y1 = 0
B(1 - x^2) y2 - y1 = 0
C(1 + x^2) y2 - x y1 = 0
D(1 - x^2) y2 + x y1 = 0
Answer & Solution
Correct answer: A. (1 - x^2) y2 - x y1 = 0
With y1 = (1 - x^2)^(-1/2), differentiating gives y2 = x (1 - x^2)^(-3/2), so (1 - x^2) y2 equals x y1.
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