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Let f(x) = kx^2 for x <= 2 and f(x) = 3 for x > 2. For continuity at x = 2, the value of k is
A3/4
B4
C4/3
D3/2
Answer & Solution
Correct answer: A. 3/4
The left value is 4k and the right limit is 3, so 4k = 3 and k = 3/4.
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