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Taking natural logs of y = [u(x)]^v(x) gives log y equal to
Av(x) log u(x)
Bv(x) / log u(x)
Cu(x) log v(x)
Dlog u(x) + log v(x)
Answer & Solution
Correct answer: A. v(x) log u(x)
The power rule for logarithms brings the exponent v(x) in front of log u(x).
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