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From 2x + 3y = sin x, obtain dy/dx.
A(2 - cos x)/3
Bcos x - 2
C(cos x - 2)/3
D(cos x + 2)/3
Answer & Solution
Correct answer: C. (cos x - 2)/3
Differentiating gives 2 + 3y' = cos x, so y' = (cos x - 2)/3.
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