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For x^3 + y^3 = a^3, what is dy/dx?
A-y^2/x^2
B-x/y
C-x^2/y^2
Dx^2/y^2
Answer & Solution
Correct answer: C. -x^2/y^2
Differentiating implicitly gives 3x^2 + 3y^2 y' = 0, so y' = -x^2/y^2.
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