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For y = x^(sin x) with x > 0, which expression gives dy/dx?
Ax^(sin x)(cos x + log x)
B(sin x) x^(sin x - 1) log x
Cx^(sin x)(cos x/x + log x)
Dx^(sin x)(sin x/x + cos x log x)
Answer & Solution
Correct answer: D. x^(sin x)(sin x/x + cos x log x)
From log y = sin x log x, differentiating gives y'/y = (sin x)/x + cos x log x.
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