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Parametrically x = t^2, y = t^3 (t nonzero); find dy/dx.
A2t/3
B3t^2/2
C3t/2
Dt/2
Answer & Solution
Correct answer: C. 3t/2
dy/dt = 3t^2 and dx/dt = 2t, so dy/dx = 3t^2 / 2t = 3t/2.
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