The speed of light in a transparent medium of refractive index $1.5$ is approximately: (speed of light in vacuum $= 3 \times 10^8$ m/s)
A$1.5 \times 10^8$ m/s
B$2.0 \times 10^8$ m/s
C$2.5 \times 10^8$ m/s
D$3.0 \times 10^8$ m/s
Answer & Solution
Correct answer: B. $2.0 \times 10^8$ m/s
Refractive index $\mu = \dfrac{c}{v}$, so $v = \dfrac{c}{\mu} = \dfrac{3 \times 10^8}{1.5} = 2 \times 10^8$ m/s.
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