The apparent depth of an object lying at the bottom of a pool of water…

Question

The apparent depth of an object lying at the bottom of a pool of water (n = 4/3) is, in terms of its real depth h,

Accepted Answer

A. {'text': '(3/4) h', 'label': 'A'}

1. Refraction at a flat surface: apparent depth = real depth × (n_observer / n_medium).
2. Viewing from air into water: apparent depth = h × (1 / (4/3)) = (3/4) h.
3. The pool looks shallower than it is; (A) inverts the ratio.
_Source: NCERT Class 12 Physics Part II, Ch 9 §9.3 'Real and apparent depth'_

Answer

{'text': '(1/4) h', 'label': 'B'}

Answer

{'text': 'h', 'label': 'C'}

Answer

{'text': '(4/3) h', 'label': 'D'}