A mass m on a vertical spring of constant k. The equilibrium extension is x0 = mg/k. The mass is set into SHM. Frequency depends on:
- Only g
- m, k, and g
- m and k only
- Only x0
Show answer and solution
Correct answer: C. m and k only
f = (1/(2π))√(k/m).
g determines equilibrium position x0, not the oscillation frequency.
SHM about equilibrium has same frequency as on horizontal frictionless surface.