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Tamil Nadu SSLC (Class 10) Triangles, Circles and Geometry — practice questions — page 2

Explore 38 free Triangles, Circles and Geometry questions in Tamil Nadu SSLC (Class 10) Mathematics. Open each question or exercise to read its content, reference answers and available explanation.

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Triangles, Circles and Geometry questions and exercises with answers

Showing questions 31–38 of 38.

Pythagoras theorem applies to which triangles?Read the answer and worked solution →In triangle ABC, DE is parallel to BC where D lies on AB and E on AC. If AD = 2 cm, DB = 3 cm and AE = 4 cm, then EC equalsRead the answer and worked solution →Two triangles have areas in the ratio 49 : 64. The ratio of their corresponding sides isRead the answer and worked solution →A vertical pole 6 m tall casts a shadow 4 m long at the same time a tower casts a shadow 28 m long. The height of the tower isRead the answer and worked solution →In a right triangle the legs measure 9 cm and 12 cm. The hypotenuse isRead the answer and worked solution →If two triangles are similar and the ratio of their perimeters is 3 : 5, then the ratio of their areas isRead the answer and worked solution →In triangle ABC, AD bisects angle A and meets BC at D. If AB = 6 cm, AC = 9 cm and BC = 10 cm, then BD equalsRead the answer and worked solution →The hypotenuse of a right triangle is 26 cm and one leg is 24 cm. The other leg isRead the answer and worked solution →

Worked practice questions

Pythagoras theorem applies to which triangles?

  1. Equilateral
  2. Right-angled
  3. Isosceles
  4. Any triangle
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Correct answer: B. Right-angled

1. Pythagoras theorem links the squares of three sides of a right triangle. 2. Specifically, hypotenuse squared equals the sum of squares of the other two sides. 3. It applies only to right-angled triangles. _Source: syllabus Mathematics, Ch 6 "Triangles", §6.5_

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In triangle ABC, DE is parallel to BC where D lies on AB and E on AC. If AD = 2 cm, DB = 3 cm and AE = 4 cm, then EC equals

  1. 5 cm
  2. 8 cm
  3. 6 cm
  4. 10 cm
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Correct answer: C. 6 cm

1. By the Basic Proportionality Theorem, AD/DB = AE/EC. 2. 2/3 = 4/EC. 3. Cross-multiply: 2 EC = 12, so EC = 6 cm. _Source: syllabus Mathematics, Ch 6 "Triangles", §6.3_

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Two triangles have areas in the ratio 49 : 64. The ratio of their corresponding sides is

  1. 14 : 16
  2. 8 : 7
  3. 49 : 64
  4. 7 : 8
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Correct answer: D. 7 : 8

1. For similar triangles, ratio of areas equals square of ratio of corresponding sides. 2. Square root of 49/64 is 7/8. 3. Hence sides are in ratio 7 : 8. _Source: syllabus Mathematics, Ch 6 "Triangles", §6.4_

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