In triangle ABC, AD bisects angle A and meets BC at D. If AB = 6 cm, AC = 9 cm and BC = 10 cm, then BD equals
A3 cm
B6 cm
C5 cm
D4 cm
Answer & Solution
Correct answer: D. 4 cm
1. By the angle bisector theorem, BD/DC = AB/AC = 6/9 = 2/3.
2. Let BD = 2k, DC = 3k. Then 2k + 3k = 10, so k = 2.
3. Hence BD = 2k = 4 cm.
_Source: syllabus Mathematics, Ch 6 "Triangles", §6.3_
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