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Rajasthan Board Class 12 (RBSE) Wave Optics — practice questions

Explore 8 free Wave Optics questions in Rajasthan Board Class 12 (RBSE) Physics. Open each question or exercise to read its content, reference answers and available explanation.

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Wave Optics questions and exercises with answers

Showing questions 1–8 of 8.

Light passes from air to glass ($n = 1.5$). Brewster's angle is:Read the answer and worked solution →HUYGENS' PRINCIPLE states that every point on a wavefront acts as a:Read the answer and worked solution →In Young's double-slit experiment, the fringe width β is given by:Read the answer and worked solution →In Young's experiment, a BRIGHT fringe (constructive interference) requires path difference = ?Read the answer and worked solution →In single-slit diffraction, the central maximum is:Read the answer and worked solution →Polarisation of light is direct experimental evidence that light is a:Read the answer and worked solution →BREWSTER'S LAW for the polarising angle θ_B relates to the refractive index n as:Read the answer and worked solution →The resolving power (RP) of a diffraction grating with N slits in the m-th order is:Read the answer and worked solution →

Worked practice questions

Light passes from air to glass ($n = 1.5$). Brewster's angle is:

  1. $30^\circ$, half the right angle on the boundary
  2. $45^\circ$, the diagonal angle for any clear glass
  3. $56.3^\circ$, since $\tan\theta_B = n = 1.5$
  4. $60^\circ$, twice the standard small angle here
Show answer and solution

Correct answer: C. $56.3^\circ$, since $\tan\theta_B = n = 1.5$

$\tan\theta_B = 1.5$, $\theta_B = \tan^{-1}(1.5) \approx 56.3^\circ$.

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HUYGENS' PRINCIPLE states that every point on a wavefront acts as a:

  1. Source of secondary spherical wavelets
  2. Reflector of all incident wave energy
  3. Polariser of the incident wave
  4. Absorber of half the wave energy
Show answer and solution

Correct answer: A. Source of secondary spherical wavelets

**Huygens' principle:** every point on a wavefront is a source of SECONDARY SPHERICAL WAVELETS. The new wavefront is the envelope of these wavelets. Used to derive Snell's law and reflection.

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In Young's double-slit experiment, the fringe width β is given by:

  1. $\beta = \lambda d / D$
  2. $\beta = D / (\lambda d)$
  3. $\beta = \lambda D / d$
  4. $\beta = \lambda / (D d)$
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Correct answer: C. $\beta = \lambda D / d$

**Young's fringe width:** β = λD/d. λ = wavelength; D = slit-to-screen distance; d = slit separation. Larger λ, larger D, smaller d → wider fringes.

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