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BREWSTER'S LAW for the polarising angle θ_B relates to the refractive index n as:
A$\sin \theta_B = n$
B$\cos \theta_B = n$
C$\tan \theta_B = n$
D$\theta_B = n × 45°$
Answer & Solution
Correct answer: C. $\tan \theta_B = n$
Brewster's law: tan θ_B = n. At this angle, reflected light is fully polarised. For glass (n = 1.5), θ_B ≈ 56.3°. For water (n = 1.33), θ_B ≈ 53°.
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