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In Young's double-slit experiment, the fringe width β is given by:
A$\beta = \lambda d / D$
B$\beta = D / (\lambda d)$
C$\beta = \lambda D / d$
D$\beta = \lambda / (D d)$
Answer & Solution
Correct answer: C. $\beta = \lambda D / d$
Young's fringe width: β = λD/d. λ = wavelength; D = slit-to-screen distance; d = slit separation. Larger λ, larger D, smaller d → wider fringes.
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