Glucose in open-chain form has a:
- Ketone group at C-2, like fructose has in the same molecule
- Aldehyde group at C-1, with four chiral carbons in the chain
- Carboxylic acid group at C-1, with five hydroxyl groups
- Ester group at C-6, with a cyclic structure in solid form
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Correct answer: B. Aldehyde group at C-1, with four chiral carbons in the chain
Glucose open chain: aldehyde at C-1 and -OH at C-2 to C-5 with -CH$_2$OH at C-6; four chiral C.