The plane through the origin and the intersection of x + y + z = 1 and 2x + 3y + 4z = 5 is
- x + y + z = 0
- 3x + 2y + z = 0
- 2x + 3y + 4z = 0
- x + 2y + 3z = 0
Show answer and solution
Correct answer: B. 3x + 2y + z = 0
The member (x+y+z-1) + λ(2x+3y+4z-5) passes through the origin when λ = -1/5, giving 3x + 2y + z = 0.