MHT-CET Differential Equations — practice questions
28 free MCQs with worked solutions. Tap any question for the answer + explanation, or practice them all in the app.
Practice MHT-CET Differential Equations in the app →The **order** of a differential equation is:The **degree** of a differential equation is:The order and degree of $x^2 \dfrac{d^2y}{dx^2} + 3x \dfrac{dy}{dx} + 4y = 0$ are respectively:The **general solution** of a differential equation contains:A **first-order, variables-separable** differential equation $f(y)\,dy = g(x)\,dx$ has solution:The differential equation $\dfrac{dy}{dx} + P(x) y = Q(x)$ (with $P, Q$ functions of $x$) is called:The integrating factor for the linear DE $\dfrac{dy}{dx} + P(x)y = Q(x)$ is:To solve a **homogeneous** differential equation of degree 1 (e.g. $dy/dx = f(y/x)$), the standard substitutioIf the rate of decay of a radioactive substance is proportional to its mass $m$ at time $t$, the differential The order of the differential equation obtained by eliminating the arbitrary constants $A$ and $B$ from $y = AThe order and degree of $ qrt{1 + (dy/dx)^2} = d^2y/dx^2$ are:Eliminate the arbitrary constant from $y^2 = 4ax$ to form the DE:The DE obtained by eliminating $c_1$ and $c_2$ from $y = c_1 e^{3x} + c_2 e^{2x}$ is:Solve $\dfrac{dy}{dx} = \dfrac{1 + y^2}{1 + x^2}$.Solve $\dfrac{dy}{dx} = e^{x+y}$.The DE $y - x \dfrac{dy}{dx} = 0$ has general solution:The general solution of $\dfrac{dy}{dx} + y = e^{-x}$ is:Solve the homogeneous DE $x\,dy/dx = x\,\tan(y/x) + y$:The particular solution of $\dfrac{dy}{dx} = e^{x+y}$ given $y(0) = 0$ is:The differential equation of the family of straight lines $y = mx + c$ (with $m, c$ arbitrary) is:Solve $ ec^2 x \cdot \tan y \, dx + ec^2 y \cdot \tan x \, dy = 0$:The order and degree of $\left(\dfrac{d^2y}{dx^2}\right)^{1/2} - \left(\dfrac{dy}{dx}\right)^{1/3} = 20$ are:Solve $\dfrac{dy}{dx} = \dfrac{y + qrt{x^2 + y^2}}{x}$.The half-life of a radioactive substance decaying by $dm/dt = -km$ (with $k > 0$) in terms of $k$ is:Newton's law of cooling: $dT/dt = -k(T - T_s)$ where $T_s$ is the surrounding temperature. The general solutioSolve $(x^2 - y^2)\,dx + 2xy\,dy = 0$.The particular solution of $\dfrac{dy}{dx} + y\tan x = ec x$ given $y(0) = 1$ is:If $y = e^x \cos x$, then $\dfrac{d^2 y}{dx^2} - 2\dfrac{dy}{dx} + 2y$ equals: