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The plane through the origin and the intersection of x + y + z = 1 and 2x + 3y + 4z = 5 is

Ax + y + z = 0
B3x + 2y + z = 0
C2x + 3y + 4z = 0
Dx + 2y + 3z = 0
Answer & Solution
Correct answer: B. 3x + 2y + z = 0
The member (x+y+z-1) + λ(2x+3y+4z-5) passes through the origin when λ = -1/5, giving 3x + 2y + z = 0.
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