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Math Olympiad Olympiad Maths — practice questions — page 7

Explore 329 free Olympiad Maths questions in Math Olympiad Mathematics. Open each question or exercise to read its content, reference answers and available explanation.

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Olympiad Maths questions and exercises with answers

Showing questions 181–210 of 329.

Razia wants 12 beads. She takes one necklace and how many loose beads?Read the answer and worked solution →A child has 2 necklaces and 5 loose beads. Her total bead count is:Read the answer and worked solution →A child gathers 10 loose beads. She can now tie them into:Read the answer and worked solution →While adding, a pupil collects 11 loose beads. She keeps one loose and carries:Read the answer and worked solution →A small 1 written above the tens column is there to remember one extra:Read the answer and worked solution →Razia has 20 beads and Reema has 9. Together they have:Read the answer and worked solution →Aarif gives 3 beads to Reema, who then has 20. Before that Reema had:Read the answer and worked solution →Reema has 20 beads and Aarif has 21. Added together they make:Read the answer and worked solution →A child has 3 necklaces and 5 loose beads. Written as a number this is:Read the answer and worked solution →Sonu has 35 beads and Aarif has 24. Sonu has more beads by:Read the answer and worked solution →Simar wants to take 7 beads away but has only 1 loose bead. She must open:Read the answer and worked solution →Simar opens one necklace beside her 1 loose bead. She now has loose beads numbering:Read the answer and worked solution →Taking 7 beads away from 11 loose beads leaves:Read the answer and worked solution →Simar takes away 1 necklace from her 2 necklaces. She is left with:Read the answer and worked solution →A child is left with 1 necklace and 4 loose beads. As a number that is:Read the answer and worked solution →In the number 47, the digit 4 stands for how many necklaces of ten?Read the answer and worked solution →In the number 47, the digit 7 stands for how many loose beads?Read the answer and worked solution →A pupil adds 16 and 8 and gets more than nine ones. She must:Read the answer and worked solution →Adding 25 and 13 gives a total of:Read the answer and worked solution →Taking 13 away from 25 leaves:Read the answer and worked solution →Two children hold 18 and 22 beads. Together they hold:Read the answer and worked solution →Catch the tensRead the answer and worked solution →Pop the adding wordsRead the answer and worked solution →Run the bead gatesRead the answer and worked solution →Slice the two digit numbersRead the answer and worked solution →Tens or onesRead the answer and worked solution →Sort the bead problemsRead the answer and worked solution →Type the answerRead the answer and worked solution →Tens and ones bingoRead the answer and worked solution →Two cats want to share one chapati fairly. Each should get a share that is:Read the answer and worked solution →

Worked practice questions

Razia wants 12 beads. She takes one necklace and how many loose beads?

  1. 05
  2. 02
  3. 03
  4. 04
Show answer and solution

Correct answer: B. 02

1. One necklace already gives ten beads. 2. Twelve take away ten leaves two. 3. So she takes 02 loose beads. _Source: syllabus Mathematics Class II, Chapter 12, Give and Take._

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A child has 2 necklaces and 5 loose beads. Her total bead count is:

  1. 25
  2. 27
  3. 23
  4. 21
Show answer and solution

Correct answer: A. 25

1. Each necklace stands for ten beads. 2. Two tens make twenty, plus five loose. 3. So the total is 25. _Source: syllabus Mathematics Class II, Chapter 12, Give and Take._

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A child gathers 10 loose beads. She can now tie them into:

  1. 4 necklace
  2. 1 necklace
  3. 2 necklace
  4. 3 necklace
Show answer and solution

Correct answer: B. 1 necklace

1. Ten loose beads are exactly one full string. 2. They are tied together to save counting. 3. So she gets 1 necklace. _Source: syllabus Mathematics Class II, Chapter 12, Give and Take._

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More Mathematics topics

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