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A child has 2 necklaces and 5 loose beads. Her total bead count is:

A25
B27
C23
D21
Answer & Solution
Correct answer: A. 25
1. Each necklace stands for ten beads. 2. Two tens make twenty, plus five loose. 3. So the total is 25. _Source: syllabus Mathematics Class II, Chapter 12, Give and Take._
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