A child has 2 necklaces and 5 loose beads. Her total bead count is:
A25
B27
C23
D21
Answer & Solution
Correct answer: A. 25
1. Each necklace stands for ten beads.
2. Two tens make twenty, plus five loose.
3. So the total is 25.
_Source: syllabus Mathematics Class II, Chapter 12, Give and Take._
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