A child has 3 necklaces and 5 loose beads. Written as a number this is:
A53
B38
C83
D35
Answer & Solution
Correct answer: D. 35
1. Necklaces count as tens, loose beads as ones.
2. Three tens and five ones are written in that order.
3. So the number is 35.
_Source: syllabus Mathematics Class II, Chapter 12, Give and Take._
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