Start learning →

A child has 3 necklaces and 5 loose beads. Written as a number this is:

A53
B38
C83
D35
Answer & Solution
Correct answer: D. 35
1. Necklaces count as tens, loose beads as ones. 2. Three tens and five ones are written in that order. 3. So the number is 35. _Source: syllabus Mathematics Class II, Chapter 12, Give and Take._
Practise this question with Quill — Math Olympiad →

Keep practising Tens and Ones

Browse all Tens and Ones questions for Math Olympiad, or explore more Mathematics topics.

Start a Tens and Ones lesson →
Related questions