Kerala SSLC (Class 10) Coordinate Geometry — practice questions
11 free MCQs with worked solutions. Tap any question for the answer + explanation, or practice them all in the app.
Practice Kerala SSLC (Class 10) Coordinate Geometry in the app →Three vertices of a parallelogram are (0, 0), (3, 5) and (6, 2). The fourth vertex equals:The fourth vertex of a parallelogram with three given vertices (1, 3), (5, 4), (2, 5) is (taking the missing vThe midpoint of the line segment joining (2, 3) and (8, 5) has coordinates:A circle is drawn with the segment joining (2, 3) and (6, 5) as a diameter. The centre of the circle has coordTwo opposite vertices of a parallelogram are at (4, 5) and (1, 3). The intersection of its diagonals lies at:The point dividing the segment joining (2, 3) and (8, 6) in the ratio 1 : 2 (counting from the first point) haThe point dividing the segment joining (1, 6) and (11, 2) in the ratio 3 : 5 (counting from the first point) hThe centre of a circle is at (1, 2) and one end of a diameter is at (3, 2). The other end of that diameter is The equation of a circle with centre (1, 4) and radius 2 in expanded form is:The equation of a circle with centre at the origin and radius 5 is:If (x, y) lies on the circle with the segment joining (0, 1) and (2, 3) as a diameter, then x² + y² − 2x − 4y