alleryThe centre of a circle is at (1, 2) and one end of a diameter is at (3, 2). The other end of that diameter is at:
A(5, 2)
B(1, 4)
C(−1, 2)
D(−1, 4)
Answer & Solution
Correct answer: C. (−1, 2)
1. The centre lies at the midpoint of the diameter.
2. If (3, 2) and (x, y) are the ends and (1, 2) is the midpoint, then (3 + x)/2 = 1 and (2 + y)/2 = 2.
3. From the x equation: x = 2 − 3 = −1; from the y equation: y = 4 − 2 = 2.
4. So the other end is (−1, 2).
5. The diameter therefore stretches from (3, 2) to (−1, 2), centred at (1, 2).
_Source: SCERT Kerala Std X Mathematics Part-2, Chapter 8-9 (pp 200-219, 2019 ed.)._
Keep practising Coordinate Geometry
Browse all Coordinate Geometry questions for Andhra Pradesh SSC (Class 10), or explore more Mathematics topics.
Related questions
Sort points into their quadrantsThe mid-point of the segment joining (-2, -3) and (4, 5) isThe distance of point (5, 0) from the origin isIf a point is reflected in the x-axis, the new co-ordinates of (a, b) becomeJudge these points and axes claimsSort points into their quadrantsFlip the cards and pair each coordinate quantity with its formula.The equation of a circle with centre at the origin and radius 5 is: