alleryThe midpoint of the line segment joining $(-6,10)$ and $(3,-8)$ is
A$\left(-\dfrac{3}{2},1\right)$
B$\left(-\dfrac{3}{2},2\right)$
C$( -3,1)$
D$\left(\dfrac{3}{2},1\right)$
Answer & Solution
Correct answer: A. $\left(-\dfrac{3}{2},1\right)$
The midpoint formula gives $\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)$.
**So the midpoint is $\left(\dfrac{-6+3}{2},\dfrac{10+(-8)}{2}\right)=\left(-\dfrac{3}{2},1\right)$.**
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