JEECUP (UP Polytechnic) Probability Density Function — practice questions
9 free MCQs with worked solutions. Tap any question for the answer + explanation, or practice them all in the app.
Practice JEECUP (UP Polytechnic) Probability Density Function in the app →For a **probability density function (p.d.f.)** $f(x)$ of a continuous random variable over support $S$, the tThe probability that a continuous random variable falls inside an interval $[c, d]$ corresponds to:$f(x) = 3x^2$ for $0 < x < 1$ is the p.d.f. of $X$. The probability $P[1/2 < X < 1]$ is:If $f(x) = kx^2(1 - x)$ for $0 < x < 1$ is the p.d.f. of $X$, the value of $k$ is:For p.d.f. $f(x) = x/8$, $0 < x < 4$, the probability $P[x < 1.5]$ is:Find $k$ if $f(x) = kx$ for $0 < x < 2$ and 0 otherwise is a valid p.d.f.For p.d.f. $f(x) = x^2/3$ for $-1 < x < 2$, the probability $P[0 < X \leq 1]$ equals:If $f(x) = x/2$ for $-2 < x < 2$ (and 0 elsewhere), is it a valid p.d.f.?For p.d.f. $f(x) = k(4 - x^2)$ for $-2 \leq x \leq 2$ (and 0 elsewhere), the value of $k$ is: