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ISC Class 12 Electric Charges and Fields — practice questions — page 2

Explore 50 free Electric Charges and Fields questions in ISC Class 12 Physics. Open each question or exercise to read its content, reference answers and available explanation.

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Electric Charges and Fields questions and exercises with answers

Showing questions 31–50 of 50.

NEET · Physics · Electric Charges & Fields · Coulomb's Law — Gap FillRead the answer and worked solution →NEET · Physics · Electric Charges & Fields · Quantity to UnitRead the answer and worked solution →Time constant of an RC circuit is:Read the answer and worked solution →The SI unit of electric potential isRead the answer and worked solution →The potential at a distance 0.30 m from a point charge of +20 nC is (k = 9 × 10⁹ N m² C⁻²)Read the answer and worked solution →Three capacitors of 2 µF each are connected in series. The equivalent capacitance isRead the answer and worked solution →An isolated conducting sphere of radius R carries a charge Q. The electric potential at its centre is (V(∞) = 0)Read the answer and worked solution →Two capacitors of 4 µF and 6 µF are connected in parallel and charged by a 10 V battery. The total charge stored isRead the answer and worked solution →NEET · Physics · Capacitors — Series or ParallelRead the answer and worked solution →Four equal point charges q sit at the corners of a square of side d. The work needed to assemble this configuration from infinity isRead the answer and worked solution →An electric dipole of moment p is placed in a uniform field E. The work done to rotate it from the orientation θ = 0 (aligned with the field) to θ = 180° isRead the answer and worked solution →Electric field at any point inside a hollow charged conductor isRead the answer and worked solution →On an equipotential surface, the work done in moving a test charge between any two points isRead the answer and worked solution →A parallel-plate capacitor in vacuum has plate area A and separation d. Its capacitance isRead the answer and worked solution →The work done in bringing a charge q from infinity to a point where the potential is V isRead the answer and worked solution →True or false: electrostaticsRead the answer and worked solution →A convex lens forms a real image at $60$ cm on one side of an object placed $20$ cm in front of it. Find the focal length of the lens.Read the answer and worked solution →Electric potential is a:Read the answer and worked solution →When light passes from one medium to another, which property remains **unchanged**?Read the answer and worked solution →NEET · Physics · Electric Charges & Fields · Force on Dipole in FieldRead the answer and worked solution →

Worked practice questions

NEET · Physics · Electric Charges & Fields · Coulomb's Law — Gap Fill

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Missing parts
  1. Answer
    4
    Choices
    1. 2
    2. 4
    3. 1/2
    4. 1/4
  2. Answer
    4
    Choices
    1. 2
    2. 4
    3. 8
    4. 16
Complete the statement
F = (1/4πε₀) · q1·q2 / r². Doubling r divides F by {0}. Doubling each charge multiplies F by {1}.
Instructions
Fill in how F scales with distance and charge.

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NEET · Physics · Electric Charges & Fields · Quantity to Unit

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Matching pairs
  1. Left
    Charge
    Right
    Coulomb (C)
  2. Left
    Electric field (E)
    Right
    N / C or V / m
  3. Left
    Potential (V)
    Right
    Volt (V)
Instructions
Match each electric quantity to its SI unit.

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Time constant of an RC circuit is:

  1. R + C
  2. R · C
  3. R / C
  4. 1 / (RC)
Show answer and solution

Correct answer: B. R · C

In an RC (Resistor-Capacitor) circuit, the time constant characterizes the rate at which a capacitor charges or discharges through a resistor. 1. **The Differential Equation**: For a charging RC circuit, the voltage across the capacitor $V_c(t)$ is governed by the equation: $$V(t) = V_0(1 - e^{-t/RC})$$ 2. **Defining the Constant**: The term in the exponent must be dimensionless. Since $t$ has units of time, the product $RC$ must also have units of time. This product is defined as the time constant $\tau$. $$\tau = R \cdot C$$ 3. **Physical Significance**: After one time constant ($t = \tau$), the capacitor has charged to approximately $63.2\%$ of its maximum value. 4. **Unit Analysis**: - Resistance $R = \frac{V}{I} = \frac{\text{Volts}}{\text{Coulombs/Second}}$ - Capacitance $C = \frac{Q}{V} = \frac{\text{Coulombs}}{\text{Volts}}$ - Multiplying them: $\frac{\text{Volts} \cdot \text{Seconds}}{\text{Coulombs}} \cdot \frac{\text{Coulombs}}{\text{Volts}} = \text{Seconds}$. Therefore, the time constant is $R \cdot C$.

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