Three capacitors of 2 µF each are connected in series. The equivalent capacitance is
A2 µF
B2/3 µF
C6 µF
D1/6 µF
Answer & Solution
Correct answer: B. 2/3 µF
1. In series, 1/Cₑ = 1/C + 1/C + 1/C = 3/C.
2. Cₑ = C/3 = 2/3 µF.
3. Option (A) is the parallel result, so the trap is for students who mix the rules.
_Source: syllabus Physics Part I, Ch 2 §2.14.1_
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