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Indian Navy SSR Three Dimensional Geometry — practice questions

Explore 28 free Three Dimensional Geometry questions in Indian Navy SSR Mathematics. Open each question or exercise to read its content, reference answers and available explanation.

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Three Dimensional Geometry questions and exercises with answers

Showing questions 1–28 of 28.

The distance between two points $P(x_1, y_1, z_1)$ and $Q(x_2, y_2, z_2)$ in three-dimensional space is:Read the answer and worked solution →Angle between line and plane: if direction of line is L and normal to plane is N, sin(angle line-plane):Read the answer and worked solution →The cosine of the angle between two lines with direction ratios $(1,2,2)$ and $(2,2,1)$ is:Read the answer and worked solution →Match each term to its definitionRead the answer and worked solution →True or false: direction cosinesRead the answer and worked solution →Direction cosines or direction ratios?Read the answer and worked solution →Order the steps: direction ratios to direction cosinesRead the answer and worked solution →Skew linesRead the answer and worked solution →Tap every pair of lines that could be skewRead the answer and worked solution →Match each equation to what it describesRead the answer and worked solution →Complete the definition of direction cosinesRead the answer and worked solution →Complete the definition of skew linesRead the answer and worked solution →True or false: angles between linesRead the answer and worked solution →Assertion and reasonRead the answer and worked solution →Spot the one that does not belongRead the answer and worked solution →Two are true, one is notRead the answer and worked solution →Reading the equationsRead the answer and worked solution →Flip and pair: symbol with meaningRead the answer and worked solution →Same plane or different planes?Read the answer and worked solution →Three of these are wrong. Find the one that holds.Read the answer and worked solution →Order the steps: angle between two lines from direction ratiosRead the answer and worked solution →Tap each statement that is true of a line's equationRead the answer and worked solution →True or false: reading the chapter's scopeRead the answer and worked solution →Match each condition to what it meansRead the answer and worked solution →The normalising relationRead the answer and worked solution →Spot the odd one outRead the answer and worked solution →Assertion and reason: equations of a lineRead the answer and worked solution →Which quantity is which?Read the answer and worked solution →

Worked practice questions

The distance between two points $P(x_1, y_1, z_1)$ and $Q(x_2, y_2, z_2)$ in three-dimensional space is:

  1. $\sqrt{(x_2 + x_1)^2 + (y_2 + y_1)^2 + (z_2 + z_1)^2}$
  2. $(x_2 - x_1)(y_2 - y_1)(z_2 - z_1)$
  3. $|x_2 - x_1| + |y_2 - y_1| + |z_2 - z_1|$
  4. $\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2 + (z_2 - z_1)^2}$
Show answer and solution

Correct answer: D. $\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2 + (z_2 - z_1)^2}$

3D distance formula extends Pythagoras into three dimensions: the distance is the square root of the sum of squared coordinate differences. Derivation: project the segment $PQ$ onto each axis to get the leg lengths $|x_2 - x_1|$, etc. Apply Pythagoras twice. Option B is the **Manhattan** (taxicab) distance, useful in some lattice problems but not the Euclidean answer.

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Angle between line and plane: if direction of line is L and normal to plane is N, sin(angle line-plane):

  1. |L · N| / (|L| |N|) — since 90° - angle(line, normal)
  2. 0
  3. tan
  4. cos
Show answer and solution

Correct answer: A. |L · N| / (|L| |N|) — since 90° - angle(line, normal)

Angle between line and plane (measured to surface, not normal) = complement of angle between line and normal. **So sin(line-plane) = cos(line-normal) = |L · N|/(|L||N|).**

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The cosine of the angle between two lines with direction ratios $(1,2,2)$ and $(2,2,1)$ is:

  1. $\tfrac{4}{9}$
  2. $\tfrac{2}{3}$
  3. $\tfrac{1}{9}$
  4. $\tfrac{8}{9}$
Show answer and solution

Correct answer: D. $\tfrac{8}{9}$

We have cosθ = (1·2+2·2+2·1)/(√9·√9). So cosθ = 8/9.

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