alleryAngle between line and plane: if direction of line is L and normal to plane is N, sin(angle line-plane):
A|L · N| / (|L| |N|) — since 90° - angle(line, normal)
B0
Ctan
Dcos
Answer & Solution
Correct answer: A. |L · N| / (|L| |N|) — since 90° - angle(line, normal)
Angle between line and plane (measured to surface, not normal) = complement of angle between line and normal.
**So sin(line-plane) = cos(line-normal) = |L · N|/(|L||N|).**
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