Brewster's angle for a glass of refractive index $\sqrt{3}$ (relative to air) is:
- $30^\circ$
- $45^\circ$
- $60^\circ$
- $90^\circ$
Show answer and solution
Correct answer: C. $60^\circ$
**Brewster's law:** $\tan i_B = \mu$.
With $\mu = \sqrt{3}$, $\tan i_B = \sqrt{3} \Rightarrow i_B = 60^\circ$.
At this angle the reflected light is completely plane-polarised, with the electric field perpendicular to the plane of incidence.