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Brewster's angle for a glass of refractive index $\sqrt{3}$ (relative to air) is:

A$30^\circ$
B$45^\circ$
C$60^\circ$
D$90^\circ$
Answer & Solution
Correct answer: C. $60^\circ$
Brewster's law: $\tan i_B = \mu$. With $\mu = \sqrt{3}$, $\tan i_B = \sqrt{3} \Rightarrow i_B = 60^\circ$. At this angle the reflected light is completely plane-polarised, with the electric field perpendicular to the plane of incidence.
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