alleryA cricket ball of mass 150 g moving at (3i+4j) m/s is hit to -(3i+4j) m/s. The magnitude of momentum change is
A0
B3.0 kg·m/s
C1.5 kg·m/s
D0.75 kg·m/s
Answer & Solution
Correct answer: C. 1.5 kg·m/s
We have Δp = m(v−u).
That is Δp = 0.15·(−2)(3i+4j).
So Δp = −0.3(3i+4j).
|Δp| = 0.3·√(9+16) = 0.3·5 = 1.5 kg·m/s.
Keep practising Laws of Motion
Browse all Laws of Motion questions for AP Intermediate 1st Year, or explore more Physics topics.
Related questions
A constant force of 6 N acts for 4 s on a 2 kg body initially at rest. The kinetic energy A stone of mass 0.5 kg is whirled in a horizontal circle of radius 1 m at constant angularA car of mass 1000 kg accelerates from rest to 20 m s⁻¹ in 5 s on a level road. The net hoA force F acts on a particle making an angle θ with its instantaneous velocity. The componNewton's second law is often written as F = m a. This form is strictly valid when:A batsman hits a 0.15 kg ball back along the line of approach without changing its speed oMomentum p of a body of mass m moving with velocity v is defined as:The SI unit of force, the newton, is defined as the force that: