A cricket ball of mass 150 g moving at (3i+4j) m/s is hit to -(3i+4j) m/s. The magnitude of momentum change is
A0
B3.0 kg·m/s
C1.5 kg·m/s
D0.75 kg·m/s
Answer & Solution
Correct answer: C. 1.5 kg·m/s
Δp = m(v−u) = 0.15·(−2)(3i+4j) = −0.3(3i+4j). |Δp| = 0.3·√(9+16) = 0.3·5 = 1.5 kg·m/s.
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