Reaction of XeF₂ with water:
AInert
BXeF₂ + 2 H₂O → Xe(OH)₂
CNo reaction
DXeF₂ + H₂O → Xe + HF + O₂ (disproportionation/hydrolysis)
Answer & Solution
Correct answer: D. XeF₂ + H₂O → Xe + HF + O₂ (disproportionation/hydrolysis)
XeF₂ slowly hydrolyzes: 2 XeF₂ + 2 H₂O → 2 Xe + 4 HF + O₂. Xenon fluorides are powerful oxidizers. XeF₄, XeF₆ also exist. Demonstrates that even 'inert' noble gases form compounds under right conditions.
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