Two point masses 3 kg each at the ends of a massless rod of length 4 m. I about axis through center perpendicular to rod:
- 48
- 36
- 24
- 12
Show answer and solution
Correct answer: C. 24
Each mass at distance 2 m from center.
We have I = sum m × r².
That is I = 3 × 2² + 3 × 2².
That is I = 12 + 12.
So I = 24 kg m².