As per your syllabus, in CH₄ atomisation requires 1665 kJ/mol. What is the MEAN C-H bond enthalpy?
- 416 kJ/mol (≈ 1665 / 4)
- 427 kJ/mol
- 100 kJ/mol
- 1665 kJ/mol
Show answer and solution
Correct answer: A. 416 kJ/mol (≈ 1665 / 4)
As per your syllabus, mean C-H = Δ_a H°/4 = 1665/4 ≈ 416 kJ/mol.
Individual successive C-H bond dissociations differ (427, 439, 452, 347).