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Indian Navy INET Chemical Kinetics — practice questions

Explore 27 free Chemical Kinetics questions in Indian Navy INET Chemistry. Open each question or exercise to read its content, reference answers and available explanation.

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Chemical Kinetics questions and exercises with answers

Showing questions 1–27 of 27.

For a reaction with Ea = 100 kJ/mol, find k₂/k₁ when T goes from 300 K to 350 K. (R = 8.314 J/mol K):Read the answer and worked solution →For a 2nd-order reaction with [A]₀ = 0.5 M and k = 0.1 L mol⁻¹ s⁻¹, half-life:Read the answer and worked solution →Order or molecularity?Read the answer and worked solution →True or false: order and molecularityRead the answer and worked solution →Read the order off the rate lawRead the answer and worked solution →Complete the definition of orderRead the answer and worked solution →True or false: where a rate law comes fromRead the answer and worked solution →Instantaneous rate or average rate?Read the answer and worked solution →Match each symbol in the Arrhenius equation to its meaningRead the answer and worked solution →Complete the definition of activation energyRead the answer and worked solution →Tap everything that raises the rate of a reactionRead the answer and worked solution →Assertion and reasonRead the answer and worked solution →The Arrhenius equationRead the answer and worked solution →Order the steps: find the order of a reactionRead the answer and worked solution →Two are true, one is notRead the answer and worked solution →Three of these are wrong. Find the one that holds.Read the answer and worked solution →Spot the one that does not belongRead the answer and worked solution →True or false: what kinetics studiesRead the answer and worked solution →Flip and pair: term with meaningRead the answer and worked solution →Tap every factor the chapter says affects the rateRead the answer and worked solution →Complete the collision theory modificationRead the answer and worked solution →Which quantity is being described?Read the answer and worked solution →Assertion and reason: rates and constantsRead the answer and worked solution →Reading the definitions backRead the answer and worked solution →Order the energy story of a reactionRead the answer and worked solution →True or false: the Arrhenius pictureRead the answer and worked solution →Spot the odd one outRead the answer and worked solution →

Worked practice questions

For a reaction with Ea = 100 kJ/mol, find k₂/k₁ when T goes from 300 K to 350 K. (R = 8.314 J/mol K):

  1. About 130
  2. About 10
  3. About 2
  4. About 0.5
Show answer and solution

Correct answer: A. About 130

We have ln(k₂/k₁) = -Ea/R × (1/T₂ - 1/T₁). That is ln(k₂/k₁) = -(100000/8.314)(1/350 - 1/300). So ln(k₂/k₁) = -12028 × (-4.76 × 10⁻⁴) ≈ 5.73. → k₂/k₁ = e^5.73 ≈ 308. Closer to 100–300 so 'about 130'-class is the right range.

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For a 2nd-order reaction with [A]₀ = 0.5 M and k = 0.1 L mol⁻¹ s⁻¹, half-life:

  1. 10 s
  2. 20 s (t₁/₂ = 1/(k[A]₀) = 1/(0.1 × 0.5))
  3. 5 s
  4. 100 s
Show answer and solution

Correct answer: B. 20 s (t₁/₂ = 1/(k[A]₀) = 1/(0.1 × 0.5))

We have t₁/₂ = 1/(k [A]₀). That is t₁/₂ = 1/(0.1 × 0.5). So t₁/₂ = 20 s. Note dependence on [A]₀ (unlike 1st order).

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Order or molecularity?

Read exercise and reference answers
Items
  1. Item
    Found experimentally
    Category
    Order
  2. Item
    Can be zero or a fraction
    Category
    Order
  3. Item
    Read off the rate law
    Category
    Order
  4. Item
    Defined only for elementary reactions
    Category
    Molecularity
  5. Item
    Limited to values 1, 2 or 3
    Category
    Molecularity
  6. Item
    Counts the species in one step
    Category
    Molecularity
Categories
  1. Item
    Order
  2. Item
    Molecularity
Order is measured; molecularity is counted from a proposed mechanism. Order can be zero or fractional, molecularity cannot. Source: syllabus Chemistry Part I, Ch 3 Chemical Kinetics.

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