The reactive electrophile in the Reimer–Tiemann reaction is
- $Cl^-$
- $OH^-$
- Dichlorocarbene $:CCl_2$
- $CHCl_3$ itself
Show answer and solution
Correct answer: C. Dichlorocarbene $:CCl_2$
$CHCl_3 + OH^- \to :CCl_2 + Cl^- + H_2O$.
The carbene attacks the ortho carbon of phenoxide.
Subsequent hydrolysis of the geminal dichloride gives $-CHO$.