For the reaction PCl5(g) ⇌ PCl3(g) + Cl2(g), if initial pressure of PCl5 is P0 and degree of dissociation is α, total pressure at equilibrium:
AP0 × α
BP0(1 - α)
CP0
DP0(1 + α)
Answer & Solution
Correct answer: D. P0(1 + α)
Initial PCl5 = P0. At equilibrium: PCl5 = P0(1-α), PCl3 = P0α, Cl2 = P0α. Total = P0(1-α) + P0α + P0α = P0(1+α).
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