Home › JEE Main › Chemistry › Chemical Equilibrium › At 500 K, Kc for N2 + 3H2 ⇌ 2NH3 is 60 (in mol⁻²…
At 500 K, Kc for N2 + 3H2 ⇌ 2NH3 is 60 (in mol⁻² L²). Kp at 500 K (R = 0.0821):
A60
B60/(RT)²
C60 × (RT)
D60 × (RT)²
Answer & Solution
Correct answer: B. 60/(RT)²
Δn_gas = 2 - 4 = -2. Kp = Kc (RT)^Δn = 60 × (0.0821 × 500)⁻² = 60 / (41.05)² ≈ 0.036 atm⁻².
Related questions
For Fe³⁺(aq) + SCN⁻(aq) ⇌ [Fe(SCN)]²⁺(aq), adding more KSCN causes the Fe³⁺ concentration The solubility of carbon dioxide in a soft drink falls as temperature rises because dissolWhen the temperature of an exothermic reaction at equilibrium is raised, the equilibrium cAdding a catalyst to a reversible reaction at equilibrium:A sealed flask of reacting gases shows no colour change for an hour. What is actually happBesides VSEPR and the Kossel Lewis approach, which two theories are listed?Which theory is abbreviated VSEPR?Why can lattice enthalpy not be calculated directly from attraction and repulsion alone?