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At 500 K, Kc for N2 + 3H2 ⇌ 2NH3 is 60 (in mol⁻² L²). Kp at 500 K (R = 0.0821):

A60
B60/(RT)²
C60 × (RT)
D60 × (RT)²
Answer & Solution
Correct answer: B. 60/(RT)²
Δn_gas = 2 - 4 = -2. Kp = Kc (RT)^Δn = 60 × (0.0821 × 500)⁻² = 60 / (41.05)² ≈ 0.036 atm⁻².
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