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Indian Navy 10+2 B.Tech Cadet Electromagnetic Induction — practice questions

Explore 5 free Electromagnetic Induction questions in Indian Navy 10+2 B.Tech Cadet Physics. Open each question or exercise to read its content, reference answers and available explanation.

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Electromagnetic Induction questions and exercises with answers

Showing questions 1–5 of 5.

Magnetic flux Φ = B A cos θ. If a coil of area 0.1 m² in B = 0.5 T is rotated from θ=0° to θ=60° in 0.2 s, average EMF:Read the answer and worked solution →A rod of length L moves with velocity v perpendicular to magnetic field B. Motional EMF:Read the answer and worked solution →In a step-down transformer with 1000:100 turn ratio (primary:secondary), 220 V input, 1 A secondary current. Primary current (ideal):Read the answer and worked solution →A capacitor C in series with inductor L (LC circuit) oscillates with frequency:Read the answer and worked solution →Phase difference between voltage and current in pure capacitor in AC:Read the answer and worked solution →

Worked practice questions

Magnetic flux Φ = B A cos θ. If a coil of area 0.1 m² in B = 0.5 T is rotated from θ=0° to θ=60° in 0.2 s, average EMF:

  1. 0.05 V
  2. 0.5 V
  3. 0.125 V
  4. 0.25 V
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Correct answer: C. 0.125 V

We have Φ₁ = 0.5 × 0.1 × cos 0. So Φ₁ = 0.05 Wb. Φ₂ = 0.5 × 0.1 × cos 60° = 0.025 Wb. ΔΦ = 0.025 Wb. EMF = |ΔΦ|/Δt = 0.025/0.2 = 0.125 V.

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A rod of length L moves with velocity v perpendicular to magnetic field B. Motional EMF:

  1. BL²v
  2. BL/v
  3. BLv
  4. B²Lv
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Correct answer: C. BLv

EMF = BLv (motional EMF, derived from F = qv × B on charges in the rod). Used in generators, rail guns. Independent of resistance of the rod itself.

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In a step-down transformer with 1000:100 turn ratio (primary:secondary), 220 V input, 1 A secondary current. Primary current (ideal):

  1. 0.1 A
  2. 1 A
  3. 100 A
  4. 10 A
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Correct answer: A. 0.1 A

V₁I₁ = V₂I₂ for ideal transformer. V₂ = 220 × (100/1000) = 22 V. I₁ = (V₂I₂)/V₁ = (22 × 1)/220 = 0.1 A. (Or: I₁/I₂ = N₂/N₁ = 1/10.)

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