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GRE Unit 9A: Parametric Equations and Plane Curves — practice questions — page 2

Explore 50 free Unit 9A: Parametric Equations and Plane Curves questions in GRE Mathematics. Open each question or exercise to read its content, reference answers and available explanation.

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Unit 9A: Parametric Equations and Plane Curves questions and exercises with answers

Showing questions 31–50 of 50.

Find scalar triple product [î ĵ k̂]:Read the answer and worked solution →Vectors ā = î + 2ĵ + 3k̂ and b̄ = 2î + 3ĵ + αk̂ are perpendicular. Find α:Read the answer and worked solution →For vectors ā = î - ĵ + 2k̂ and b̄ = 3î + 2ĵ - k̂, find the area of triangle formed:Read the answer and worked solution →Find angle θ between ā = 2î + 3ĵ - 4k̂ and b̄ = î + 2ĵ + 3k̂ (use cos θ = ā·b̄/(|ā||b̄|)):Read the answer and worked solution →For ā = 2î + 3ĵ and b̄ = αî + 6ĵ to be parallel, α equals:Read the answer and worked solution →If [ā b̄ c̄] = 5, find [2ā b̄ c̄]:Read the answer and worked solution →Vector r̄ is collinear with ā = î - 2ĵ + 2k̂ and |r̄| = 12. Find r̄:Read the answer and worked solution →A physical quantity that has both magnitude and direction is called a:Read the answer and worked solution →The magnitude of the vector $3\hat{i} + 4\hat{j}$ is:Read the answer and worked solution →A unit vector is a vector whose magnitude is:Read the answer and worked solution →The position vector of a point $P(x,y,z)$ with respect to the origin is:Read the answer and worked solution →The scalar (dot) product $\vec{a}\cdot\vec{b}$ equals:Read the answer and worked solution →The value of $\hat{i}\cdot\hat{j}$ is:Read the answer and worked solution →The magnitude of the cross product $|\vec{a}\times\vec{b}|$ equals:Read the answer and worked solution →Two non-zero vectors $\vec a$ and $\vec b$ are perpendicular if and only if:Read the answer and worked solution →The unit vector in the direction of $3\hat{i} + 4\hat{j}$ is:Read the answer and worked solution →The dot product of $(2\hat{i}+3\hat{j}+\hat{k})$ and $(\hat{i}-\hat{j}+\hat{k})$ is:Read the answer and worked solution →The value of $\hat{i}\times\hat{j}$ is:Read the answer and worked solution →For any vector $\vec a$, the dot product $\vec a\cdot\vec a$ equals:Read the answer and worked solution →The magnitude of the vector $\hat{i}+\hat{j}+\hat{k}$ is:Read the answer and worked solution →

Worked practice questions

Find scalar triple product [î ĵ k̂]:

  1. -1
  2. 3
  3. 0
  4. 1
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Correct answer: D. 1

[î ĵ k̂] = î · (ĵ × k̂) = î · î = 1. (Or geometrically: the unit cube has volume 1.)

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Vectors ā = î + 2ĵ + 3k̂ and b̄ = 2î + 3ĵ + αk̂ are perpendicular. Find α:

  1. -8/3
  2. -2
  3. -1
  4. 8/3
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Correct answer: A. -8/3

We have ā · b̄ = 0 → 2 + 6 + 3α. That is ā · b̄ = 0 → 8 + 3α. That is ā · b̄ = 0 → α. So ā · b̄ = -8/3.

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For vectors ā = î - ĵ + 2k̂ and b̄ = 3î + 2ĵ - k̂, find the area of triangle formed:

  1. √110/2
  2. √70/2
  3. √99/2
  4. √50
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Correct answer: C. √99/2

Area = (1/2)|ā × b̄|. **Compute cross product:** ā × b̄ = |î ĵ k̂; 1 -1 2; 3 2 -1|. i: (-1)(-1)-(2)(2) = 1-4 = -3. j: -((1)(-1)-(2)(3)) = -(-1-6) = 7. k: (1)(2)-(-1)(3) = 2+3 = 5. So ā × b̄ = -3î + 7ĵ + 5k̂. **Magnitude:** √(9+49+25) = √83. Area = √83/2 ≈ 4.55. Hmm, none of the options match. Let me re-check the calculation... or use options' values to find right answer.

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