The dot product of $(2\hat{i}+3\hat{j}+\hat{k})$ and $(\hat{i}-\hat{j}+\hat{k})$ is:
A4
B0
C$-2$
D6
Answer & Solution
Correct answer: B. 0
(2)(1)+(3)(−1)+(1)(1) = 2 − 3 + 1 = 0.
Related questions
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